Skip to main content

How I Finally Understood HashMap Usage in Continuous Subarray Sum (After Failing with Sliding Window)

Problem Background

While solving the Continuous Subarray Sum problem on LeetCode, I initially felt confident because the word subarray immediately triggered my sliding window intuition. I had been practicing two pointers and sliding window patterns consistently, so my brain naturally tried to force that approach here.

Why Sliding Window Failed for Me

I tried hard to find a condition to either expand or shrink the window. But no matter how I looked at it, something felt off.

  • The sum does not behave monotonically
  • There is no clear rule to shrink the window
  • Checking divisibility by k gives no directional hint

That’s when I realized this problem does not belong to the sliding window family. The confusion I was facing was actually a signal that I was applying the wrong pattern.

The YouTube Insight That Changed Everything

After watching a YouTube tutorial focused only on intuition, one key idea finally clicked:

If the same remainder appears again while taking prefix sum modulo k, the sum in between is divisible by k.

This was the missing mental bridge. I wasn’t supposed to track window size — I was supposed to track state repetition.

Why HashMap Suddenly Made Sense

Instead of thinking in terms of subarrays, I started thinking in terms of prefix states:

  • Maintain a running prefix sum
  • Store prefix_sum % k in a hashmap
  • If the same remainder appears again after at least 2 indices, we’ve found the answer

This explains why a HashMap is required — we’re not searching, we’re remembering.

My Final Code

Here is the exact implementation I used (and the one I referenced in my GitHub repository):

class Solution:
    def checkSubarraySum(self, nums: List[int], k: int) -> bool:
        h_set = {0: -1}
        s = 0
        for index, i in enumerate(nums):
            s += i
            if s % k in h_set:
                if index - h_set[s % k] >= 2:
                    return True
            else:
                h_set[s % k] = index
        return False

GitHub Solution

You can view the full solution on GitHub here:
https://github.com/RohitSingh-04/Python-Solutions/blob/main/LC523.py

What I Learned from This Problem

  • Not every subarray problem is sliding window
  • If there is no shrinking condition, sliding window is a red flag
  • Repeated prefix states often indicate HashMap usage
  • YouTube intuition videos are useful when used correctly

Final Thoughts

Initially, HashMap usage felt unintuitive and forced. But after understanding the remainder logic, it now feels inevitable. This problem taught me that getting stuck is part of pattern recognition — and sometimes, the breakthrough comes from realizing why your first idea doesn’t work.

This was a solid reminder that learning DSA is not about memorizing solutions, but about reshaping how you think.

Comments

Popular posts from this blog

LeetCode 88 Explained: Four Approaches, Mistakes, Fixes & the Final Optimal Python Solution

Evolving My Solution to “Merge Sorted Array” A practical, beginner-friendly walkthrough showing four versions of my code (from a naive approach to the optimal in-place two-pointer solution). Includes explanations, complexity and ready-to-paste code. Problem Summary You are given two sorted arrays: nums1 with size m + n (first m are valid) nums2 with size n Goal: Merge nums2 into nums1 in sorted order in-place . Version 1 — Beginner Approach (Extra List) I merged into a new list then copied back. Works, but not in-place and uses extra memory. class Solution: def merge(self, nums1, m, nums2, n): result = [] p1 = 0 p2 = 0 for _ in range(m+n): if p1 >= m: result.extend(nums2[p2:n]) break elif p2 >= n: result.extend(nums1[p1:m]) break elif nu...

Introducing CodeMad: Your Ultimate Universal IDE with Custom Shortcuts

Introducing CodeMad: Your Ultimate Multi-Language IDE with Custom Shortcuts Welcome to the world of CodeMad, your all-in-one Integrated Development Environment (IDE) that simplifies coding and boosts productivity. Developed in Python, CodeMad is designed to make your coding experience smoother and more efficient across a variety of programming languages, including C, C++, Java, Python, and HTML. Whether you're a beginner or an experienced programmer, CodeMad is your go-to tool. In this blog, we'll dive deep into the workings of CodeMad, highlighting its unique features and easy installation process. The Power of Shortcuts CodeMad's intuitive interface is built around a set of powerful keyboard shortcuts that make coding a breeze. Here are some of the key shortcuts you'll find in CodeMad: Copy (Ctrl+C) : Duplicate text with ease. Paste (Ctrl+V) : Quickly insert copied content into your code. Undo (Ctrl+Z) and Redo (Ctrl+Y) : Correct mistakes and s...

Product of Array Except Self in Python | Prefix & Suffix Explained (LeetCode 238)

Problem Overview The Product of Array Except Self is a classic problem that tests your understanding of array traversal and optimization. The task is simple to state but tricky to implement efficiently. Given an integer array nums , you need to return an array such that each element at index i is equal to the product of all the elements in nums except nums[i] . The challenge is that: Division is not allowed The solution must run in O(n) time Initial Thoughts At first glance, it feels natural to compute the total product of the array and divide it by the current element. However, this approach fails because division is forbidden and handling zeroes becomes messy. This pushed me to think differently — instead of excluding the current element, why not multiply everything around it? That’s where the prefix and suffix product pattern comes in. Key Insight: Prefix & Suffix Products For every index i : Prefix product → product of all elements to t...